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10x^2-39x+36=0
a = 10; b = -39; c = +36;
Δ = b2-4ac
Δ = -392-4·10·36
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-39)-9}{2*10}=\frac{30}{20} =1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-39)+9}{2*10}=\frac{48}{20} =2+2/5 $
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